THEOREM OF THE DAY Sendov’s Conjecture (a Theorem Under Construction!) Let f (z) be a polynomial of degree n ≥ 2, all of whose zeros lie in the closed unit disk. Then for any zero z0 of f (z), the closed unit disk wi

Source URL: theoremoftheday.org

Lower bounds for a polynomial in terms of its coefficients Mehdi Ghasemi and Murray Marshall Abstract. We determine new sufficient conditions in terms of the coefficients for a polynomial f ∈ R[X] of degree 2d (d ≥ 1

Source URL: math.usask.ca

Chapter 4: Constant-degree Polynomial Partitioning Adam Sheffer May 1, 2015 In this chapter we present a different way of deriving incidence bounds by using polynomial partitioning. This method yields slightly worse boun

Source URL: www.math.caltech.edu

LOWER BOUNDS FOR A POLYNOMIAL IN TERMS OF ITS COEFFICIENTS MEHDI GHASEMI AND MURRAY MARSHALL Abstract. Recently Lasserre [6] gave a sufficient condition in terms of the coefficients for a polynomial f ∈ R[X] of degree

Source URL: math.usask.ca

Sum-product estimate for |A + A| + |f (A) + B| for a quadratic polynomial f Boris Bukh and Jacob Tsimerman Theorem 1. Let f ∈ Fp [X] be a polynomial of degree 2. Then for all sets A, B ⊂ Fp √

Source URL: www.borisbukh.org

A Generalized Method for Proving Polynomial Calculus Degree Lower Bounds Mladen Mikˇsa KTH Royal Institute of Technology Stockholm, Sweden

Source URL: computationalcomplexity.org

Practice) + (-6) = -) + (-5) = -) + (-1) = -) = (-3) + 6 = + 3

Source URL: www.mathusee.com

• Degree of a polynomial
• Polynomials
• Mathematics
• Partial fraction

A Constant Bound for the Periods of Parallel Chip-firing Games with Many Chips Paul Myer Kominers and Scott Duke Kominers Abstract. We prove that any parallel chip-firing game on a graph G with at least 4|E(G)| − |V (G

Source URL: www.pkoms.com

• Matroid theory
• Polynomials
• Tutte polynomial
• Degree
• Tree
• NP-complete problems
• Path decomposition
• Handshaking lemma
• Graph theory
• Mathematics
• Theoretical computer science

PROBLEM-SOLVING MASTERCLASS WEEK 4 1. Let p(z) be a polynomial of degree n, all of whose zeros have absolute value 1 in the complex plane. Put g(z) = p(z)/zn/2 . Show that all zeros of g 0 (z) = 0 have absolute value 1.

Source URL: math.stanford.edu

Number Fields Introduction A number field is a field of finite degree over Q. By the Primitive Element Theorem, any number field K = Q(α) for some α ∈ K. The minimal polynomial Let K be a number field and let α ∈

Source URL: www.jchl.co.uk